Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers? n2 + n – 210 = 0 n2 + n – 105 = 0 2n2 + 2n + 210 = 0 2n2 + 2n + 105 = 0

The equation that can be used to solve for n, the smaller of the two numbers would be n² + n - 210 = 0.What is a quadratic equation?A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.If we use n to be the smaller number of two integer numbers, then the next consecutive number is n + 1.The product of those two numbers would become n × (n + 1) = n (n + 1).Half of that product is n (n + 1) / 2.And the question states that the equation is equal to 105, so the equation becomes,n (n + 1) / 2 = 105Now we have to simplify that equation until we get an expression equal to one of the choices,Multiply both sides by 2 n (n + 1) = 210n² + n = 210Subtract 210 from both sidesn² + n - 210 = 0Thus, the equation formed is the quadratic equation.Learn more about quadratic equations;brainly.com/question/13197897